If you write y=tanx=sinx/cosx, when cosx=0, you have a null denominator. The points of discontinuity of the function y=tanx are in x=pi/2+kpi " where " k in ZZ", that are the solutions of …

When I answer trig graphing questions, I like to show a "basic graph" of the function - for example, #y=sinx#, and then walk through and show the changes step by step to the graph. But if I put …

Apr 29, 2017 · Here is my proof, which is wrong? I am proving sinx - sinxtanx =0 sinx = sinxtanx 1 = tanx Apparently I HAVE to factor out sinx. Why is that? Trigonometry

What is the first derivative of #x+ tanx# and how do you find the slope of the normal to the curve where #x=pi#? What is the slope of the line tangent to the graph of #x^2xy+y^2=7#? What is …

Mar 14, 2018 · sinx(1 −2sin2x +sin4x)sec5(x) = tanx We can now factor the parenthesis: sinx(1 −sin2x)(1 − sin2x)sec5(x) = tanx A very familiar modified Pythagorean identity will now be …

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lim_ (x->0) (1-cosx)/tan^2x = 1/2 Using the trigonometric identities: 2sin^2 (x/2) = 1-cosx and: tan x = (2tan (x/2))/ (1-tan^2 (x/2)) we have: (1-cosx)/tan^2x= (2sin ...

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How do you differentiate f (x) = x tan 3x + x3 tan x using the product rule?

Given tan (cotx)=cot (tanx) => tan (cotx)=tan (pi/2-tanx) =>cotx+tanx=pi/2 =>cosx/sinx+sinx/cosx=pi/2 => (cos^2x+sin^2x)/ (sinxcosx)=pi/2 =2/ (2sinxcosx)=pi/2 =>2 ...