A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Nov 25, 2013 · It is a pointer to function that returns int* and accepts int* and pointer to function that returns int* (and accepts undefined number of parameters; see comments).

Sep 25, 2010 · That second memory address, then, is expected to hold an int. Do note that, while you are declaring a pointer to an int, the actual int is not allocated. So it is valid to say int *i = …

Jan 28, 2013 · Closed 5 years ago. Is there a difference between int[] array = new int[10]; and int array[] = new int[10]; ? Both do work, and the result is exactly the same. Which one is quicker …

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

Feb 15, 2015 · The construct (int *) &var, where var is a char, takes a pointer to var, and then converts it to a pointer of a different type (namely int). The program later writes an int value …

Aug 24, 2016 · The question "what is the difference between int* and int []?" is a less trivial question than most people will think of: it depends on where it is used. In a declaration, like …

64 I prefer int* i because i has the type "pointer to an int", and I feel this makes it uniform with the type system. Of course, the well-known behavior comes in, when trying to define multiple …

An int variable holds a 32 bit signed integer value. An Integer (with capital I) holds a reference to an object of (class) type Integer, or to null. Java automatically casts between the two; from …

Apr 21, 2011 · 29 int and unsigned int are two distinct integer types. (int can also be referred to as signed int, or just signed; unsigned int can also be referred to as unsigned.) As the names …